On which of the following lines does the point of intersection of the line $\frac{x - 4}{2} = \frac{y - 5}{2} = \frac{z - 3}{1}$ and the plane $x + y + z = 2$ lie?

  • A
    $\frac{x + 3}{3} = \frac{4 - y}{3} = \frac{z + 1}{-2}$
  • B
    $\frac{x - 4}{1} = \frac{y - 5}{1} = \frac{z - 5}{-1}$
  • C
    $\frac{x - 1}{1} = \frac{y - 3}{2} = \frac{z + 4}{-5}$
  • D
    $\frac{x - 2}{2} = \frac{y - 3}{2} = \frac{z + 3}{3}$

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